8 MOLS(36) can be constructed from a (36,9,1) difference matrix over
G = Z2 X Z2 X Z3 X Z3.

Denote the element of G by 18a+9b+3c+d

Then

 0  3  6  9 12 15 18 21 24 27 30 33  1  4  7 10 13 16
19 22 25 28 31 34  2  5  8 11 14 17 20 23 26 29 32 35

 0  6  3 32 29 35  7  4  1  5  2  8 15 12  9 11 17 14
31 28 34 13 10 16 30 27 33 26 23 20 19 25 22 21 18 24

 0  1  2  3  4  5 21 22 23  9 10 11 27 28 29 24 25 26
18 19 20 15 16 17 33 34 35  6  7  8 30 31 32 12 13 14

 0  2  1 15 17 16  3  5  4 30 32 31 24 26 25 21 23 22
 9 11 10  6  8  7 12 14 13 27 29 28 33 35 34 18 20 19

 0  4  8 12 16 11 15 10 14 33 28 32 29 30 34  5  6  1
 35 27 31 20 21 25 19 23 24 22 26 18  7  2  3 13 17  9

 0  8  4 21 20 25 28 33 32 23 19 24 26 22 18  7  3  2
 10 15 14  9 17 13 35 31 27 12 11 16  5  1  6 34 30 29

 0  5  7 27 32 34 12 17 10 25 18 23 11 13 15 26 19 21
 8  1  3 30 35 28 22 24 20 16  9 14 31 33 29  2  4  6

 0  7  5 18 25 23 30 28 35 14  9 16 34 32 27 13 11 15
 4  2  6 24 22 20 17 12 10 29 33 31 26 21 19  1  8  3

and a row of all zeroes give a (36,9,1) difference matrix.