![]()
![[Graphics:images/TEST_P~1.HTM_gr_2.gif]](images/TEST_P~1.HTM_gr_2.gif)
![]()
![]()
![]()
![]()


![]()
![]()

![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()


![]()

![]()
![]()

![]()
![]()
![]()
![]()
![]()

![]()
![]()
![]()
![]()

![]()


![]()
Solution 1
![]()
Solution 2
![[Graphics:images/TEST_P~1.HTM_gr_46.gif]](images/TEST_P~1.HTM_gr_46.gif)
Solution 3
![]()
Solution 4
![]()
Solution 5
![[Graphics:images/TEST_P~1.HTM_gr_49.gif]](images/TEST_P~1.HTM_gr_49.gif)
![[Graphics:images/TEST_P~1.HTM_gr_50.gif]](images/TEST_P~1.HTM_gr_50.gif)
Solution 6
![[Graphics:images/TEST_P~1.HTM_gr_51.gif]](images/TEST_P~1.HTM_gr_51.gif)
![[Graphics:images/TEST_P~1.HTM_gr_52.gif]](images/TEST_P~1.HTM_gr_52.gif)
Solution 7
![]()
![]()
Solution 8
![]()
![]()
![]()
Solution 9
![]()
![[Graphics:images/TEST_P~1.HTM_gr_59.gif]](images/TEST_P~1.HTM_gr_59.gif)
![]()
Solution 10
![]()
![]()
Solution 11
![]()
![]()
![]()
![]()
![]()
![]()
x = -- 2 or x = 17
Solution 12
![]()
The number of 3-element subsets with three even elements is C(4 , 3) =
= 4 and the number of 3-elements subsets with two odd elements and one even element is C(5 , 2) · 4 =
· 4 = 40. Then the number of 3-element subsets with even sum is 4 + 40 = 44 and the probability of such a sum is
=
.
Solution 13
![]()
![]()
![]()
![]()
![]()
Solution 14
![]()
![]()
![]()
![]()
![]()
Solution 15
![]()
![]()
![]()
Solution 16
![]()
![[Graphics:images/TEST_P~1.HTM_gr_88.gif]](images/TEST_P~1.HTM_gr_88.gif)
![]()
![]()
![[Graphics:images/TEST_P~1.HTM_gr_91.gif]](images/TEST_P~1.HTM_gr_91.gif)
Solution 17
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Solution 18
![]()
![]()
![]()
![]()
Solution 19
![]()
![]()
![]()
Solution 20
![]()
![]()
![]()
![]()
![]()
Solution 21
![[Graphics:images/TEST_P~1.HTM_gr_115.gif]](images/TEST_P~1.HTM_gr_115.gif)
![[Graphics:images/TEST_P~1.HTM_gr_116.gif]](images/TEST_P~1.HTM_gr_116.gif)
Solution 22
![[Graphics:images/TEST_P~1.HTM_gr_117.gif]](images/TEST_P~1.HTM_gr_117.gif)
![]()
![]()
![]()
![]()
![]()
Solution 23
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Solution 24
![[Graphics:images/TEST_P~1.HTM_gr_130.gif]](images/TEST_P~1.HTM_gr_130.gif)
![[Graphics:images/TEST_P~1.HTM_gr_131.gif]](images/TEST_P~1.HTM_gr_131.gif)
Solution 25
![[Graphics:images/TEST_P~1.HTM_gr_132.gif]](images/TEST_P~1.HTM_gr_132.gif)
Solution 26
![[Graphics:images/TEST_P~1.HTM_gr_133.gif]](images/TEST_P~1.HTM_gr_133.gif)
![]()
![]()
Solution 27
![[Graphics:images/TEST_P~1.HTM_gr_136.gif]](images/TEST_P~1.HTM_gr_136.gif)
![]()
![]()
![[Graphics:images/TEST_P~1.HTM_gr_139.gif]](images/TEST_P~1.HTM_gr_139.gif)
![]()
![]()
![]()
![]()
Solution 28
![]()
![]()
![]()
![]()
![]()
Solution 29
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Solution 30
![[Graphics:images/TEST_P~1.HTM_gr_158.gif]](images/TEST_P~1.HTM_gr_158.gif)
![]()
![]()
![]()
Solution 31
![]()
![]()
![]()
![]()
![[Graphics:images/TEST_P~1.HTM_gr_166.gif]](images/TEST_P~1.HTM_gr_166.gif)
Solution 32
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Solution 33
![]()
![]()
![]()
Solution 34
![[Graphics:images/TEST_P~1.HTM_gr_177.gif]](images/TEST_P~1.HTM_gr_177.gif)
Solution 35
![[Graphics:images/TEST_P~1.HTM_gr_178.gif]](images/TEST_P~1.HTM_gr_178.gif)
Solution 36
![[Graphics:images/TEST_P~1.HTM_gr_179.gif]](images/TEST_P~1.HTM_gr_179.gif)
Solution 37
![[Graphics:images/TEST_P~1.HTM_gr_180.gif]](images/TEST_P~1.HTM_gr_180.gif)
Solution 38
![[Graphics:images/TEST_P~1.HTM_gr_181.gif]](images/TEST_P~1.HTM_gr_181.gif)
Solution 39
![]()
Solution 40
![[Graphics:images/TEST_P~1.HTM_gr_183.gif]](images/TEST_P~1.HTM_gr_183.gif)
Solution 41
![[Graphics:images/TEST_P~1.HTM_gr_184.gif]](images/TEST_P~1.HTM_gr_184.gif)