Section 6.4
Let f(t) be a continuous function
on the closed interval [a, b]. If I
divide the interval into n equal subintervals, each piece will be length
For
each subinterval, pick a point. (If I were using the right-hand method, I would
pick the right endpoint of the interval.)
So out of interval I, pick the point xi. At that point, I will go up to the function
and build a rectangle whose height is f(xi). The area of that rectangle is
. We can add all the
areas of all of the rectangles:
. So if we let the
number of rectangles increase without bound we have
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This is called the definite integral of f(x) with limits of integration a and b.
Example:
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This is the same as asking the area between f(t) = t + 3 and the t-axis on the interval [1, 4]. The graph of this is this. We are looking for the area of the trapezoid. This is a rectangle (base = 3, height = 4) topped by a triangle (base = 3, height = 3).
Area of the trapezoid = area rectangle + area of triangle = 12 + 9/2 = 33/2

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Example: Evaluate ![]()
Plot y = 3t + 2
We are looking for the area of the gray region.
rectangle (base = 5, height = 2), triangle (base = 5, height = 17- 2)

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Example: Evaluate
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Plot ![]()

This is asking for the area of one-fourth of a circle with radius 2
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Example:
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When the function is negative, the “area” is negative. So we would have a negative area plus a positive area. The 2 triangles have the same magnitude of area.
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